Komentar di: REMIDI KIMIA KLAS XII SMA SHAFTA SBY http://casper11.wordpress.com/2008/01/21/remidi-kimia-klas-xii-sma-shafta-sby/ Just another WordPress.com weblog Fri, 20 Jun 2008 13:02:16 +0000 http://wordpress.com/ hourly 1 Oleh: Anonymous http://casper11.wordpress.com/2008/01/21/remidi-kimia-klas-xii-sma-shafta-sby/#comment-220 Anonymous Thu, 31 Jan 2008 04:18:00 +0000 http://casper11.wordpress.com/2008/01/21/remidi-kimia-klas-xii-sma-shafta-sby/#comment-220 Nama : M.Santoso<br/>kelas XII IPA<br/>absent:24<br/>hal:remidi kimia<br/><br/>Diket : W1 = 600 gram <br/>W2= 27 gram <br/>Tb = 100,13°C<br/>Dit : Mr…………………?<br/>Jawab : <br/>Delta Tb = (100,13-100)°C = 0,03°C<br/><br/>Delta Tb = W2 / Mr x 1000 / W2 x Kb<br/><br/>0,13 = 27/Mrx1000/600x0,51°C/molal<br/><br/>0,13 mr = 27000 / 600 x 0,51°C<br/><br/>= 0,0176 gr/mol Nama : M.Santoso
kelas XII IPA
absent:24
hal:remidi kimia

Diket : W1 = 600 gram
W2= 27 gram
Tb = 100,13°C
Dit : Mr…………………?
Jawab :
Delta Tb = (100,13-100)°C = 0,03°C

Delta Tb = W2 / Mr x 1000 / W2 x Kb

0,13 = 27/Mrx1000/600×0,51°C/molal

0,13 mr = 27000 / 600 x 0,51°C

= 0,0176 gr/mol

]]> Oleh: Anonymous http://casper11.wordpress.com/2008/01/21/remidi-kimia-klas-xii-sma-shafta-sby/#comment-219 Anonymous Wed, 30 Jan 2008 13:48:00 +0000 http://casper11.wordpress.com/2008/01/21/remidi-kimia-klas-xii-sma-shafta-sby/#comment-219 nama; aRiZ caTUR Y<br/>kelas; XII Ipa<br/>no. absen: 03<br/><br/>Dik: Mp: 72 gram <br/>Mrp: 18<br/>Po: 20,1 cm Hg<br/>Mt: 18 gram<br/>Mrt: 180<br/>Dit: DeLta P<br/>Jwb:<br/>Mol t = gram = 18:180 = 0.1 mol<br/>Mr <br/><br/>Mol p = Gram = 72 :18 = 4mol<br/>Mr <br/><br/>Delta P = Po . Xt<br/><br/>= Po nt<br/>nt + np<br/><br/>= 20.1 0.1<br/>0.1 + 4 <br/><br/>= 20.1 . 0.024<br/>=0.482 cm Hg nama; aRiZ caTUR Y
kelas; XII Ipa
no. absen: 03

Dik: Mp: 72 gram
Mrp: 18
Po: 20,1 cm Hg
Mt: 18 gram
Mrt: 180
Dit: DeLta P
Jwb:
Mol t = gram = 18:180 = 0.1 mol
Mr

Mol p = Gram = 72 :18 = 4mol
Mr

Delta P = Po . Xt

= Po nt
nt + np

= 20.1 0.1
0.1 + 4

= 20.1 . 0.024
=0.482 cm Hg

]]> Oleh: Anonymous http://casper11.wordpress.com/2008/01/21/remidi-kimia-klas-xii-sma-shafta-sby/#comment-218 Anonymous Wed, 30 Jan 2008 13:45:00 +0000 http://casper11.wordpress.com/2008/01/21/remidi-kimia-klas-xii-sma-shafta-sby/#comment-218 nama : nEnNy aPRIYantI<br/>kelas :i2 ipa<br/>no.absen:26<br/><br/>diketahui : w1= 600 gr<br/>w2= 27 gr<br/>Tb= 100,13 derajat <br/>Kb air= 0,51 derajat C/molal<br/><br/>dit : Mr senyawa tsb ?<br/><br/>jwb : delta Tb= 100,13 - 100 = 0,13<br/>delta Tb= w2/Mr.1000/w1.Kb<br/>0,13= (27/Mr.1000/600).0,51<br/>0,13= 13770/600Mr<br/>78 Mr= 13770<br/>Mr = 13770/78<br/>Mr = 176,63 nama : nEnNy aPRIYantI
kelas :i2 ipa
no.absen:26

diketahui : w1= 600 gr
w2= 27 gr
Tb= 100,13 derajat
Kb air= 0,51 derajat C/molal

dit : Mr senyawa tsb ?

jwb : delta Tb= 100,13 – 100 = 0,13
delta Tb= w2/Mr.1000/w1.Kb
0,13= (27/Mr.1000/600).0,51
0,13= 13770/600Mr
78 Mr= 13770
Mr = 13770/78
Mr = 176,63

]]> Oleh: Anonymous http://casper11.wordpress.com/2008/01/21/remidi-kimia-klas-xii-sma-shafta-sby/#comment-217 Anonymous Wed, 30 Jan 2008 13:43:00 +0000 http://casper11.wordpress.com/2008/01/21/remidi-kimia-klas-xii-sma-shafta-sby/#comment-217 nama : anita andayani<br/>kelas :i2 ipa<br/>no.absen:04<br/><br/>diketahui : w1= 600 gr<br/>w2= 27 gr<br/>Tb= 100,13 derajat <br/>Kb air= 0,51 derajat C/molal<br/><br/>dit : Mr senyawa tsb ?<br/><br/>jwb : delta Tb= 100,13 - 100 = 0,13<br/>delta Tb= w2/Mr.1000/w1.Kb<br/>0,13= (27/Mr.1000/600).0,51<br/>0,13= 13770/600Mr<br/>78 Mr= 13770<br/>Mr = 13770/78<br/>Mr = 176,6 nama : anita andayani
kelas :i2 ipa
no.absen:04

diketahui : w1= 600 gr
w2= 27 gr
Tb= 100,13 derajat
Kb air= 0,51 derajat C/molal

dit : Mr senyawa tsb ?

jwb : delta Tb= 100,13 – 100 = 0,13
delta Tb= w2/Mr.1000/w1.Kb
0,13= (27/Mr.1000/600).0,51
0,13= 13770/600Mr
78 Mr= 13770
Mr = 13770/78
Mr = 176,6

]]> Oleh: Anonymous http://casper11.wordpress.com/2008/01/21/remidi-kimia-klas-xii-sma-shafta-sby/#comment-216 Anonymous Wed, 30 Jan 2008 13:39:00 +0000 http://casper11.wordpress.com/2008/01/21/remidi-kimia-klas-xii-sma-shafta-sby/#comment-216 nama; nurfitasari<br/>kelas; XII Ipa<br/><br/><br/>Dik: Mp: 72 gram <br/>Mrp: 18<br/>Po: 20,1 cm Hg<br/>Mt: 18 gram<br/>Mrt: 180<br/>Dit: DP<br/>Jwb:<br/>Mol t = gram = 18:180 = 0.1 mol<br/>Mr <br/><br/>Mol p = Gram = 72 :18 = 4mol<br/>Mr <br/><br/>DP = Po . Xt<br/><br/>= Po nt<br/>nt + np<br/><br/>= 20.1 0.1<br/>0.1 + 4 <br/><br/>= 20.1 . 0.024<br/>=0.482 cm Hg nama; nurfitasari
kelas; XII Ipa

Dik: Mp: 72 gram
Mrp: 18
Po: 20,1 cm Hg
Mt: 18 gram
Mrt: 180
Dit: DP
Jwb:
Mol t = gram = 18:180 = 0.1 mol
Mr

Mol p = Gram = 72 :18 = 4mol
Mr

DP = Po . Xt

= Po nt
nt + np

= 20.1 0.1
0.1 + 4

= 20.1 . 0.024
=0.482 cm Hg

]]> Oleh: Anonymous http://casper11.wordpress.com/2008/01/21/remidi-kimia-klas-xii-sma-shafta-sby/#comment-215 Anonymous Wed, 30 Jan 2008 13:38:00 +0000 http://casper11.wordpress.com/2008/01/21/remidi-kimia-klas-xii-sma-shafta-sby/#comment-215 nama; nurfitasari<br/>kelas; XII Ipa<br/><br/><br/>Dik: Mp: 72 gram <br/>Mrp: 18<br/>Po: 20,1 cm Hg<br/>Mt: 18 gram<br/>Mrt: 180<br/>Dit: DP<br/>Jwb:<br/>Mol t = gram = 18:180 = 0.1 mol<br/>Mr <br/><br/>Mol p = Gram = 72 :18 = 4mol<br/>Mr <br/><br/>DP = Po . Xt<br/><br/>= Po nt<br/>nt + np<br/><br/>= 20.1 0.1<br/>0.1 + 4 <br/><br/>= 20.1 . 0.024<br/>=0.482 cm Hg<br/><br/><br/><br/>pak emailku gak bs d buka. kmren dh buat tp gk bs. jd email saya gabung sm emailnya neny.maap ya pak................ nama; nurfitasari
kelas; XII Ipa

Dik: Mp: 72 gram
Mrp: 18
Po: 20,1 cm Hg
Mt: 18 gram
Mrt: 180
Dit: DP
Jwb:
Mol t = gram = 18:180 = 0.1 mol
Mr

Mol p = Gram = 72 :18 = 4mol
Mr

DP = Po . Xt

= Po nt
nt + np

= 20.1 0.1
0.1 + 4

= 20.1 . 0.024
=0.482 cm Hg

pak emailku gak bs d buka. kmren dh buat tp gk bs. jd email saya gabung sm emailnya neny.maap ya pak…………….

]]> Oleh: Anonymous http://casper11.wordpress.com/2008/01/21/remidi-kimia-klas-xii-sma-shafta-sby/#comment-212 Anonymous Wed, 30 Jan 2008 05:42:00 +0000 http://casper11.wordpress.com/2008/01/21/remidi-kimia-klas-xii-sma-shafta-sby/#comment-212 Nama : kiful minalmes<br/>kelas XII IPA<br/>absen: 16<br/><br/>Diket : W1 = 600 gram <br/>W2= 27 gram <br/>Tb = 100,13°C<br/>Dit : Mr…………………?<br/>Jawab :<br/>Delta Tb = (100,13-100)°C = 0,03°C<br/><br/>Delta Tb = W2 / Mr x 1000 / W2 x Kb<br/><br/>0,13 = 27/Mrx1000/600x0,51°C/molal<br/><br/>0,13 mr = 27000 / 600 x 0,51°C<br/><br/>= 0,0176 gr/mol Nama : kiful minalmes
kelas XII IPA
absen: 16

Diket : W1 = 600 gram
W2= 27 gram
Tb = 100,13°C
Dit : Mr…………………?
Jawab :
Delta Tb = (100,13-100)°C = 0,03°C

Delta Tb = W2 / Mr x 1000 / W2 x Kb

0,13 = 27/Mrx1000/600×0,51°C/molal

0,13 mr = 27000 / 600 x 0,51°C

= 0,0176 gr/mol

]]> Oleh: Anonymous http://casper11.wordpress.com/2008/01/21/remidi-kimia-klas-xii-sma-shafta-sby/#comment-211 Anonymous Wed, 30 Jan 2008 05:40:00 +0000 http://casper11.wordpress.com/2008/01/21/remidi-kimia-klas-xii-sma-shafta-sby/#comment-211 Nama : Vanny Adha<br/>kelas XII IPA<br/>absen: 40<br/><br/>Diket : W1 = 600 gram <br/>W2= 27 gram <br/>Tb = 100,13°C<br/>Dit : Mr…………………?<br/>Jawab :<br/>Delta Tb = (100,13-100)°C = 0,03°C<br/><br/>Delta Tb = W2 / Mr x 1000 / W2 x Kb<br/><br/>0,13 = 27/Mrx1000/600x0,51°C/molal<br/><br/>0,13 mr = 27000 / 600 x 0,51°C<br/><br/>= 0,0176 gr/mol Nama : Vanny Adha
kelas XII IPA
absen: 40

Diket : W1 = 600 gram
W2= 27 gram
Tb = 100,13°C
Dit : Mr…………………?
Jawab :
Delta Tb = (100,13-100)°C = 0,03°C

Delta Tb = W2 / Mr x 1000 / W2 x Kb

0,13 = 27/Mrx1000/600×0,51°C/molal

0,13 mr = 27000 / 600 x 0,51°C

= 0,0176 gr/mol

]]> Oleh: Anonymous http://casper11.wordpress.com/2008/01/21/remidi-kimia-klas-xii-sma-shafta-sby/#comment-210 Anonymous Wed, 30 Jan 2008 05:39:00 +0000 http://casper11.wordpress.com/2008/01/21/remidi-kimia-klas-xii-sma-shafta-sby/#comment-210 Nama : M, Abdul Q.<br/>Kelas : XII-IPA / 23<br/><br/>Diket : w glukosa = 18 gr<br/>w air = 72 gr<br/>Mr C6H12O6 = 180<br/>Mr H2O = 18<br/>P° = 20,1mmHg<br/>Dit : Delta P………………...?<br/>Jawab :<br/>n1 C6H12O6 = 18 gr x 1mol/180 gr = 0,1 mol<br/><br/>n2 H2O = 72 gr x 1mol/18 gr = 4 mol<br/><br/>X C6H12O6 = n1 / n1+n2<br/>= 0,1 / 0,1+4 = 0,024<br/><br/><br/>Delta P = P° x X C6H12O6<br/>= 2010 mmHg x 0,024<br/>= 48,24 mmHg Nama : M, Abdul Q.
Kelas : XII-IPA / 23

Diket : w glukosa = 18 gr
w air = 72 gr
Mr C6H12O6 = 180
Mr H2O = 18
P° = 20,1mmHg
Dit : Delta P…………………?
Jawab :
n1 C6H12O6 = 18 gr x 1mol/180 gr = 0,1 mol

n2 H2O = 72 gr x 1mol/18 gr = 4 mol

X C6H12O6 = n1 / n1+n2
= 0,1 / 0,1+4 = 0,024

Delta P = P° x X C6H12O6
= 2010 mmHg x 0,024
= 48,24 mmHg

]]> Oleh: Anonymous http://casper11.wordpress.com/2008/01/21/remidi-kimia-klas-xii-sma-shafta-sby/#comment-204 Anonymous Wed, 30 Jan 2008 03:55:00 +0000 http://casper11.wordpress.com/2008/01/21/remidi-kimia-klas-xii-sma-shafta-sby/#comment-204 Nama : Randhie Jihadillah<br/>Kelas : XII-IPA / 47<br/><br/>Diket : w glukosa = 18 gr<br/>w air = 72 gr<br/>Mr C6H12O6 = 180<br/>Mr H2O = 18<br/>P° = 20,1mmHg<br/>Dit : Delta P………………...?<br/>Jawab :<br/>n1 C6H12O6 = 18 gr x 1mol/180 gr = 0,1 mol<br/><br/>n2 H2O = 72 gr x 1mol/18 gr = 4 mol<br/><br/>X C6H12O6 = n1 / n1+n2<br/>= 0,1 / 0,1+4 = 0,024<br/><br/><br/>Delta P = P° x X C6H12O6<br/>= 2010 mmHg x 0,024<br/>= 48,24 mmHg Nama : Randhie Jihadillah
Kelas : XII-IPA / 47

Diket : w glukosa = 18 gr
w air = 72 gr
Mr C6H12O6 = 180
Mr H2O = 18
P° = 20,1mmHg
Dit : Delta P…………………?
Jawab :
n1 C6H12O6 = 18 gr x 1mol/180 gr = 0,1 mol

n2 H2O = 72 gr x 1mol/18 gr = 4 mol

X C6H12O6 = n1 / n1+n2
= 0,1 / 0,1+4 = 0,024

Delta P = P° x X C6H12O6
= 2010 mmHg x 0,024
= 48,24 mmHg

]]>